using doctest style
https://docs.python.org/3/library/doctest.html https://numpy.org/doc/stable/docs/howto_document.html#sections (section 15)
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@ -229,19 +229,20 @@ class Symmetry:
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Return inverse pole figure color if requested.
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Bases are computed from
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basis = {'cubic' : np.linalg.inv(np.array([[0.,0.,1.], # direction of red
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[1.,0.,1.]/np.sqrt(2.), # direction of green
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[1.,1.,1.]/np.sqrt(3.)]).T), # direction of blue
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'hexagonal' : np.linalg.inv(np.array([[0.,0.,1.], # direction of red
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[1.,0.,0.], # direction of green
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[np.sqrt(3.),1.,0.]/np.sqrt(4.)]).T), # direction of blue
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'tetragonal' : np.linalg.inv(np.array([[0.,0.,1.], # direction of red
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[1.,0.,0.], # direction of green
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[1.,1.,0.]/np.sqrt(2.)]).T), # direction of blue
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'orthorhombic' : np.linalg.inv(np.array([[0.,0.,1.], # direction of red
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[1.,0.,0.], # direction of green
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[0.,1.,0.]]).T), # direction of blue
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}
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>>> basis = {'cubic' : np.linalg.inv(np.array([[0.,0.,1.], # direction of red
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... [1.,0.,1.]/np.sqrt(2.), # direction of green
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... [1.,1.,1.]/np.sqrt(3.)]).T), # direction of blue
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... 'hexagonal' : np.linalg.inv(np.array([[0.,0.,1.], # direction of red
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... [1.,0.,0.], # direction of green
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... [np.sqrt(3.),1.,0.]/np.sqrt(4.)]).T), # direction of blue
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... 'tetragonal' : np.linalg.inv(np.array([[0.,0.,1.], # direction of red
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... [1.,0.,0.], # direction of green
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... [1.,1.,0.]/np.sqrt(2.)]).T), # direction of blue
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... 'orthorhombic': np.linalg.inv(np.array([[0.,0.,1.], # direction of red
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... [1.,0.,0.], # direction of green
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... [0.,1.,0.]]).T), # direction of blue
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... }
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"""
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if self.lattice == 'cubic':
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basis = {'improper':np.array([ [-1. , 0. , 1. ],
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