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95f6edfb66ef42d774a5a34581f19052.jpg | ||
README.md |
README.md
Forensics 101
The main idea finding the flag using basic forensics training.
Step-1:
After we download the given image 95f6edfb66ef42d774a5a34581f19052.jpg
from the cloud, we just try simple techniques.
Step-2:
I first tried a very basic strings 95f6edfb66ef42d774a5a34581f19052.jpg
Step-3:
It just gave me this output:
JFIF
, #&')*)
-0-(0%()(
((((((((((((((((((((((((((((((((((((((((((((((((((
L?~f
:UwR
y>2|
*'?-
yhH_&
Lmz'
+f[
!"1$246B`35A
au>
~b*D
F_X:D
[ElC
him8
lr|.
L{2^
]]te
tBfE
j_s7Os/[i
W="'
"fkO
G&,ke:
eM_F
8O:J
9)/m>&
[P{!
}EI5#
a~Wt,1
]<e<
g:rc
"1Pa
ujM^P
P#3a
vFGO
ZniFi
%a ?}
2AQaq 0B#@r
\xr>
\37g
4=i#N
F:Jx
.`Ot
v[xU
|='u
{~T{@
LX.9
?mBx
L1QG
lIYB+
|] %
QTj?:
$*,-
pk4D
4R gX
$mmk
_QSK
b)^L
a[T=
mpj<N;
!1AQaq
x'<L
we|C{
iiR8
"'A*
aZ(4
cj}+
NL7'4
u-kF3n
x cd
s}F3_Y
$+Ym
zrsq
f}]@
L&/F
&F'$,
| *
ktWxn
yLX*s]
pT)J
eR-3
SG=3\Y
JK%0
h"(p
!01Q
%^cJ
H|cO
!10AQ
'([P
!1AQaq
s`%"
X`3d'
'P]!
;#_l
ABx=~
"r&"
0YAP
ch-h
XoXrl
l0Je
V^_W
xp7p
v{*{8
=k"$TW3G
1)j!
7y}U
<~0GD
n%CeoQ=m8
`"n<P
i}\D
X`(
8kF=
~9%]Tn
flag{wow!_data_is_cool}
$lqU
AG{u
Xm*CnC
@'hnQ
ax+p
bdQG
D_ O
Step-4:
Finally the flag becomes:
flag{wow!_data_is_cool}