CTFlearn-Writeups/Cryptography/RSA Noob/Flag.py

19 lines
403 B
Python

from Crypto.Util.number import inverse
import binascii
e = 1
c = 9327565722767258308650643213344542404592011161659991421
n = 245841236512478852752909734912575581815967630033049838269083
# From factordb
p = 416064700201658306196320137931
q = 590872612825179551336102196593
phi = (p-1) * (q-1)
d = inverse(e,phi)
m = pow(c,d,n)
hex_str = hex(m)[2:] # Removing '0x'
print(binascii.unhexlify(hex_str))