forked from 170010011/fr
167 lines
5.7 KiB
Python
167 lines
5.7 KiB
Python
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""" Sketching-based Matrix Computations """
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# Author: Jordi Montes <jomsdev@gmail.com>
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# August 28, 2017
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import numpy as np
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from scipy._lib._util import check_random_state, rng_integers
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from scipy.sparse import csc_matrix
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__all__ = ['clarkson_woodruff_transform']
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def cwt_matrix(n_rows, n_columns, seed=None):
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r""""
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Generate a matrix S which represents a Clarkson-Woodruff transform.
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Given the desired size of matrix, the method returns a matrix S of size
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(n_rows, n_columns) where each column has all the entries set to 0
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except for one position which has been randomly set to +1 or -1 with
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equal probability.
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Parameters
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----------
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n_rows: int
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Number of rows of S
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n_columns: int
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Number of columns of S
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seed : None or int or `numpy.random.RandomState` instance, optional
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This parameter defines the ``RandomState`` object to use for drawing
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random variates.
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If None (or ``np.random``), the global ``np.random`` state is used.
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If integer, it is used to seed the local ``RandomState`` instance.
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Default is None.
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Returns
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-------
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S : (n_rows, n_columns) csc_matrix
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The returned matrix has ``n_columns`` nonzero entries.
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Notes
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-----
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Given a matrix A, with probability at least 9/10,
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.. math:: \|SA\| = (1 \pm \epsilon)\|A\|
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Where the error epsilon is related to the size of S.
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"""
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rng = check_random_state(seed)
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rows = rng_integers(rng, 0, n_rows, n_columns)
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cols = np.arange(n_columns+1)
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signs = rng.choice([1, -1], n_columns)
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S = csc_matrix((signs, rows, cols),shape=(n_rows, n_columns))
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return S
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def clarkson_woodruff_transform(input_matrix, sketch_size, seed=None):
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r""""
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Applies a Clarkson-Woodruff Transform/sketch to the input matrix.
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Given an input_matrix ``A`` of size ``(n, d)``, compute a matrix ``A'`` of
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size (sketch_size, d) so that
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.. math:: \|Ax\| \approx \|A'x\|
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with high probability via the Clarkson-Woodruff Transform, otherwise
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known as the CountSketch matrix.
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Parameters
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----------
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input_matrix: array_like
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Input matrix, of shape ``(n, d)``.
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sketch_size: int
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Number of rows for the sketch.
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seed : None or int or `numpy.random.RandomState` instance, optional
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This parameter defines the ``RandomState`` object to use for drawing
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random variates.
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If None (or ``np.random``), the global ``np.random`` state is used.
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If integer, it is used to seed the local ``RandomState`` instance.
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Default is None.
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Returns
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-------
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A' : array_like
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Sketch of the input matrix ``A``, of size ``(sketch_size, d)``.
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Notes
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-----
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To make the statement
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.. math:: \|Ax\| \approx \|A'x\|
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precise, observe the following result which is adapted from the
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proof of Theorem 14 of [2]_ via Markov's Inequality. If we have
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a sketch size ``sketch_size=k`` which is at least
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.. math:: k \geq \frac{2}{\epsilon^2\delta}
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Then for any fixed vector ``x``,
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.. math:: \|Ax\| = (1\pm\epsilon)\|A'x\|
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with probability at least one minus delta.
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This implementation takes advantage of sparsity: computing
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a sketch takes time proportional to ``A.nnz``. Data ``A`` which
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is in ``scipy.sparse.csc_matrix`` format gives the quickest
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computation time for sparse input.
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>>> from scipy import linalg
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>>> from scipy import sparse
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>>> n_rows, n_columns, density, sketch_n_rows = 15000, 100, 0.01, 200
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>>> A = sparse.rand(n_rows, n_columns, density=density, format='csc')
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>>> B = sparse.rand(n_rows, n_columns, density=density, format='csr')
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>>> C = sparse.rand(n_rows, n_columns, density=density, format='coo')
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>>> D = np.random.randn(n_rows, n_columns)
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>>> SA = linalg.clarkson_woodruff_transform(A, sketch_n_rows) # fastest
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>>> SB = linalg.clarkson_woodruff_transform(B, sketch_n_rows) # fast
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>>> SC = linalg.clarkson_woodruff_transform(C, sketch_n_rows) # slower
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>>> SD = linalg.clarkson_woodruff_transform(D, sketch_n_rows) # slowest
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That said, this method does perform well on dense inputs, just slower
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on a relative scale.
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Examples
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--------
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Given a big dense matrix ``A``:
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>>> from scipy import linalg
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>>> n_rows, n_columns, sketch_n_rows = 15000, 100, 200
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>>> A = np.random.randn(n_rows, n_columns)
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>>> sketch = linalg.clarkson_woodruff_transform(A, sketch_n_rows)
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>>> sketch.shape
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(200, 100)
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>>> norm_A = np.linalg.norm(A)
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>>> norm_sketch = np.linalg.norm(sketch)
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Now with high probability, the true norm ``norm_A`` is close to
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the sketched norm ``norm_sketch`` in absolute value.
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Similarly, applying our sketch preserves the solution to a linear
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regression of :math:`\min \|Ax - b\|`.
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>>> from scipy import linalg
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>>> n_rows, n_columns, sketch_n_rows = 15000, 100, 200
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>>> A = np.random.randn(n_rows, n_columns)
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>>> b = np.random.randn(n_rows)
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>>> x = np.linalg.lstsq(A, b, rcond=None)
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>>> Ab = np.hstack((A, b.reshape(-1,1)))
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>>> SAb = linalg.clarkson_woodruff_transform(Ab, sketch_n_rows)
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>>> SA, Sb = SAb[:,:-1], SAb[:,-1]
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>>> x_sketched = np.linalg.lstsq(SA, Sb, rcond=None)
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As with the matrix norm example, ``np.linalg.norm(A @ x - b)``
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is close to ``np.linalg.norm(A @ x_sketched - b)`` with high
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probability.
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References
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----------
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.. [1] Kenneth L. Clarkson and David P. Woodruff. Low rank approximation and
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regression in input sparsity time. In STOC, 2013.
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.. [2] David P. Woodruff. Sketching as a tool for numerical linear algebra.
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In Foundations and Trends in Theoretical Computer Science, 2014.
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"""
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S = cwt_matrix(sketch_size, input_matrix.shape[0], seed)
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return S.dot(input_matrix)
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